(x-2)[2x-2(3+x)]-12=

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Solution for (x-2)[2x-2(3+x)]-12= equation: 


Simplifying
(x + -2)[2x + -2(3 + x)] + -12 = 0

Reorder the terms:
(-2 + x)[2x + -2(3 + x)] + -12 = 0
(-2 + x)[2x + (3 * -2 + x * -2)] + -12 = 0
(-2 + x)[2x + (-6 + -2x)] + -12 = 0

Reorder the terms:
(-2 + x)[-6 + 2x + -2x] + -12 = 0

Combine like terms: 2x + -2x = 0
(-2 + x)[-6 + 0] + -12 = 0
(-2 + x)[-6] + -12 = 0

Reorder the terms for easier multiplication:
-6(-2 + x) + -12 = 0
(-2 * -6 + x * -6) + -12 = 0
(12 + -6x) + -12 = 0

Reorder the terms:
12 + -12 + -6x = 0

Combine like terms: 12 + -12 = 0
0 + -6x = 0
-6x = 0

Solving
-6x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-6'.
x = 0

Simplifying
x = 0

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